Question

15xsquare-16x-31=0 pls solve this ​

Answer 1

this is the answer for the question

Answer 2

Answer:

$\mathfrak\pink{Answer}$

$we \: have \: \\ \\ \implies \: 15 {x}^{2} - 16x - 31 = 0 \\ \\ \implies \: 15 {x}^{2} + 15x - 31x - 31 = 0 \\ \\ \implies \: 15x(x + 1) - 31(x + 1) = 0 \\ \\ \implies \: (15x - 31)(x + 1) = 0 \\ \\ \implies \: \boxed{x = - 1 \: or \: \frac{31}{15}} \\ \\ \\ \: hope \: it \: helps \: u \:$