Math, asked by CodeMonkey, 9 months ago

15years ago , a man was 5 times old as his son .if at present ,he is twice as old as his son ,find their present age .

Answers

Answered by annamaryjoseph977
4

Answer:

let man be x

let son be y

5 years ago

mans age is  x-15

son is y-15

5 times his son

=x-15=5(y-15).......................1

at present

x=2y.................................2

2 in 1

2y-15=5y-75

5y-2y=75-15

=3y=60

  therefore  y=20

x=2y

therefore x=2*20

x=40

Step-by-step explanation:

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