Question

15z³-20z²+13z-12 by 3z-6?​

Answer 1

Answer:

54

Step-by-step explanation:

3z-6 =0

3z = 6

z=2--(1)

15z^3-20z^2+13z-12--(2)

substituting z=2 in (2)

15(2)^3-20(2)^2+13(2)-12

120-80+26-12

54

Answer 2

Answer:

$15z {}^{3} - 20 {z}^{2} + 13z - 12 \div 3z - 6 \\ 3z - 6 = 0 \\ 3z = 6 \\ z = 6 \div 3 = 2 \\ sub \: z \: value \: in \: eq \: \\ = 15 \times {2}^{3} - 20 \times {2}^{2} + 13 \times 2 - 12 \\ = 120 - 80 + 26 - 12 \\ = 146 - 92 = 54$