Chemistry, asked by aditipachore, 1 month ago

16.00 gram of oxygen at S.T.P would occupy a volume of ?

Answers

Answered by llSᴡᴇᴇᴛHᴏɴᴇʏll

2

Answer:

1 mole of a gas occupy =22.4L volume at STP therefore, 16gO2 gas =0.5 mole of O2 gas will occupy =0.5×22.41=11.2L at STP.

Hope my answer will help you..

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