Question

{16+(12÷4)}-{(8÷3)+(-5-6)

Answer 1

Step-by-step explanation:

If A={3,6,9,12,15,18,21},B={4,8,12,16,20},

C={2,4,6,8,10,12,14,16},D={5,10,15,20}; find

(i) A−B

(ii) A−C

(iii) A−D

(iv) B−A

(v) C−A

(vi) D−A

(vii) B−C

(viii) B−D

(ix) C−B

(x) D−B

(xi) C−D

(xii) D−C

Easy

Solution

verified

Verified by

A={3,6,9,12,15,18,21}

B={4,8,12,16,20}

C={2,4,6,8,10,12,14,16}

D={5,10,15,20}

(i) A−B={3,6,9,15,18,21}

(ii) A−C={3,9,15,18,21}

(iii) A−D={3,6,9,12,18,21}

(iv) B−A={4,8,16,20}

(v) C−A={2,4,8,10,14,16}

(vi) D−A={5,10,20}

(vii) B−C={20}

(viii) B−D={4,8,12,16}

(ix) C−B={2,6,10,14}

(x) D−B={5,10,15}

(xi) C−D={2,4,6,8,12,14,16}

(xii) D−C={5,15,20}

Answer 2

Answer:

The value of $16+(12\div 4)}-{(8\div3)+(-5-6)$ is 5.34 .

Step-by-step explanation:

Given -

$16+(12\div 4)}-{(8\div3)+(-5-6)$

To find -

The value of $16+(12\div 4)}-{(8\div3)+(-5-6)$

Solution -

For simplifying we will use BODMAS,

As per BODMAS rule,

B for Bracket

O for Of

D for Divide

M for Multiply

A for Addition

S for Subtraction

Given ,

$16+(12\div 4)}-{(8\div3)+(-5-6)$

1. Divide 12 by 4 and 8 by 3 we get

= $16+(3)}-{(2.66)+(-5-6)$

= $16+3-2.66-5-6$

2.Add 16 and 3 we get

= $19-2.66-5-6$

Two (-) sign comes together then addition occurred .

So, add 5 and 6 we get

= $19-2.66-11$

Add 2.66 and 11 we get

= $19-13.66$

= $5.34$

∴ The value of $16+(12\div 4)}-{(8\div3)+(-5-6)$ is 5.34 .