Question

16 ^{2 {}^{3x + 4 } } = 2 ^{4 {}^{3x + 2 } }
16​

Answer 1

Answer:

243)(n/5) x 32n + 19n x 3n – 1= (35)(n/5) x 32n + 1(32)n x 3n – 1= (35 x (n/5) x 32n + 1)(32n x 3n – 1)= 3n x 32n + 132n x 3n – 1= 3(n + 2n + 1)3(2n + n – 1)=33n + 133n – 1= 3(3n + 1 – 3n + 1) = 32 = 9.12.1 + 1 = ? ... C. 1 D. am + n. Answer &