Math, asked by shradhayadav301159, 4 months ago

16-2(3y+5)= 4(y-2)
solve the equation​

Answers

Answered by mamidipuspamma
1

Answer:

Distribute:

16 - 2 (3y + 5) = 4 (y - 2)

16 - 6y - 10 = 4 (y - 2)

Subtract the numbers:

16 - 6y - 10 = (y - 2 )

6 - 6y = 4 (y - 2)

Rearrange terms:

6 - 6y =4 (y - 2)

- 6y + 6 = 4 (y - 2)

Distribute:

-6y + 6 = 4 (y - 2)

-6y + 6 = 4y -8

Subtract 6 from both sides of the equation:

-6y + 6 = 4y - 8

-6y + 6 - 6 = 4y - 8 - 6

Solution:. Y = 7/5

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