(16^-2*4^3)/(8^-2)
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Answer:
16^-2*4^3/8^-2
=(2^4)^-2*(2^2)^3/(2^3)^-2
=2^-8*2^6/2^-6
=2^(-8+6)/2^-6. [a^m*a^n=a^(m+n)]
=2^-2/2^-6
=2^[(-2)-(-6)]. [a^m/a^n=a^(m-n)]
=2^(-2+6)
=2^4
=16
Hope it helps
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