Question

= 16
. (2)
Prove that, the sum of the squares of the diagonals of a rhombus is equal
to the sum of the squares of the sides.
Prove that using the Pythagoras theorem
Given : PQRS is a rhombus. Diagonals PR
and SQ intersect each other at
point T
To prove : PS² + SR? + QR? + PQP = PR? + QS?​

Answer 1

Step-by-step explanation:

hi friend

what you need to do is instead of parallelogram write Rhombus. all the steps are same. if you need help , ask me

By Roshni