Question

16(21-3m)^2-12(3m-21) factorize

Answer 1

$16(21-3m)^2-12(3m-21) \\ \\ =16(21-3m)^2 + 12(21 - 3m) \\ \\ = (21 - 3m)\big[16(21 - 3m) + 12\big] \\ \\ = (21 - 3m)\big[16 \times 21 - 16 \times 3m + 12\big] \\ \\ = (21 - 3m)\big[336 - 48m + 12\big] \\ \\ = (21 - 3m)(348 - 48m) \\ \\ = 3(7 - m) \times 12(29 - 4m) \\ \\ = 36(7 - m)(29 - 4m)$

Answer 2

Step-by-step explanation:

$\begin{lgathered}16(21-3m)^2-12(3m-21) \\ \\ =16(21-3m)^2 + 12(21 - 3m) \\ \\ = (21 - 3m)\big[16(21 - 3m) + 12\big] \\ \\ = (21 - 3m)\big[16 \times 21 - 16 \times 3m + 12\big] \\ \\ = (21 - 3m)\big[336 - 48m + 12\big] \\ \\ = (21 - 3m)(348 - 48m) \\ \\ = 3(7 - m) \times 12(29 - 4m) \\ \\ = 36(7 - m)(29 - 4m) \\\end{lgathered}$