Question

16+24=b1 find the value of b​

Answer 1

Answer:

=b1=16+24

=b=40/1

hence b=40

Answer 2

Question :-

If a+b=6 and a-b=4 then what is the value of a²+b²?

Solution :-

Given that,  

a+b=6………………………………..(1)  

a-b=4…………………………………(2)  

Adding equation (1) and (2),we get,  

(a+b)+(a-b)=10  

=> a+b+a-b=10  

=> 2a=10  

=> 2a/2=10/2  

=> a=5  

Putting a=5 in equation (1),we get,  

5+b=6  

=> b=6–5  

=> b=1  

Now,  

a^2+b^2  

=(5)^2+(1)^2  

=25+1  

=26  

2nd Method:  

a+b=6  

On squaring both sides,  

(a+b)^2=(6)^2  

=> a^2+2ab+b^2=36…………………….(1)  

a-b=4  

On squaring both sides,  

(a-b)^2=(4)^2  

=a^2–2ab+b^2=16……………..………….(2)  

Adding equation (1) and (2), we get,  

(a^2+2ab+b^2)+(a^2–2ab+b^2)=36+16  

=> a^2+2ab+b^2+a^2–2ab+b^2=52  

=> a^2+a^2+b^2+b^2+2ab-2ab=52  

=> 2a^2+2b^2=52  

=> 2(a^2+b^2)=52  

=> a^2+b^2=52/2  

=>a^2+b^2=26  

Hence, a^2+b^2=26 .  

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