Question

(16)^2x+3 = (64)^x+3,then 4^2x-2 =

Answer 1

(16)^2x+3 = (64)^x+3

(4^2)^2x+3 = (4^3)^x+3
⇒4^2(2x+3) = 4^3(x+3)
⇒4^(4x+6) = 4^(3x+9)
⇒4x+6 = 3x+9 since a^m =a^n then m=n
⇒4x-3x=9-6
x= 3 ---(1)
4^2x-2
= 4^2*3-2 from (1)
=4^6-2
=4^4
=256