Math, asked by kausarmaryam9, 8 months ago

16/3 - [ 7/3 ÷ { 3/4 - 1/2 × ( 7/10 - 3/5)}]​

Answers

Answered by Liyutsararename
1

Answer:

Step-by-step explanation:

16/3 - [ 7/3 ÷ { 3/4 - 1/2 × ( 7/10 - 3*2/5*2)}] first of all ​make denominators same

16/3 - [ 7/3 ÷ { 3/4 - 1/2 × ( 7/10 - 6/10)}]

16/3 - [ 7/3 ÷ { 3/4 - 1/2 × ( 7-6/10)}]

16/3 - [ 7/3 ÷ { 3/4 - 1/2 × ( 1/10)}]​​​

16/3 - [ 7/3 ÷ { 3/4 - 1*2/2*2 × ( 1/10)}] here also make denominators same

16/3 - [ 7/3 ÷ { 3/4 - 2/4 × ( 1/10)}]​

16/3 - [ 7/3 ÷ { 3-2/4 × ( 1/10)}]​​​​​​​​

16/3 - [ 7/3 ÷ { 1/4 × 1/10}]​​​​​​​​

16/3 - [ 7/3 ÷ { 1/40}]​​​​​​​​

16/3 - [ 7/3 ÷  1/40]

16/3 - [ 7/3 x 40/1]

16/3 - [ 280/3]

16/3 -  280/3

16-280/3

=-264/3

=-88

u can only subtract and add if the denominators are same and for making denominators same take L.C.M.....​​​​​​​

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