Question

16-3p=2/3p+5 What is the value of p?

Answer 1

Answer:

$3$

Step-by-step explanation:

$16-3p=\frac{2}{3}p+5$

⇒ $16-5-3p=\frac{2}{3} p$

⇒ $11-3p=\frac{2}{3}p$

⇒ $3(11-3p)=2p$

⇒ $33-9p=2p$

⇒ $33-9p-2p=0$

⇒ $33-11p=0$

⇒ $-11p=-33$

⇒ $p=-33/-11$

⇒ $p=3$

Answer 2

16 - 3P = 2/(3P + 5)

or, (16 - 3P ) × (3P + 5) = 2

or, 16(3P + 5) - 3P(3P + 5) = 2

or, 48P + 80 - 9P² - 15P = 2

or, -9P² + 33P + 80 - 2 = 0

or, -9P² + 33P + 78 = 0

or, 9P² - 33P - 78 = 0

P = {33 ± √(33² + 4 × 78 × 9)}/18

P = (11 ± √433)/6

hence, P = $\frac{11}{6}+\frac{\sqrt{433}}{6}$ and $\frac{11}{6}-\frac{\sqrt{433}}{6}$