Question

16(3x-5)-10(4x-8)=40​

Answer 1

Step-by-step explanation:

or, 48x-80-40x+80=40

or,8x=40

or,x=5

Answer 2

Step-by-step explanation:

16(3x + -5) + -10(4x + -8) = 40

Reorder the terms:

16(-5 + 3x) + -10(4x + -8) = 40

(-5 * 16 + 3x * 16) + -10(4x + -8) = 40

(-80 + 48x) + -10(4x + -8) = 40

Reorder the terms:

-80 + 48x + -10(-8 + 4x) = 40

-80 + 48x + (-8 * -10 + 4x * -10) = 40

-80 + 48x + (80 + -40x) = 40

Reorder the terms:

-80 + 80 + 48x + -40x = 40

Combine like terms: -80 + 80 = 0

0 + 48x + -40x = 40

48x + -40x = 40

Combine like terms: 48x + -40x = 8x

8x = 40

Solving

8x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '8'.

x = 5

Simplifying

x = 5