Question

16(3x-5)-10(4x-8)=40

Answer 1

$\huge{heya\:mate}$

$<u><b><i>$

16(3x-5)-10(4x-8)=40

48x-80-40x+80=40

8x=40

x=5

:
$\huge{x=5}$

Answer 2

16(3x-5)_10(4x-8)=40 48x-80-40x+80=40

8x=40

X=5

16(3(5)-5)-10(4(5)-8)

16(15-5)-10(20-8)

16*10-10*12

160-120

40 that is equal to RHS