Math, asked by thugriderx, 1 year ago

16^4 x root 16^-1/4

Answers

Answered by Anonymous
19

Answer:

We are provided to multply

 16^4 \: by \:\sqrt{16^{-1/4}}

Now we must know that

 a^m \times a^n = a^{m+n}

:- When a number is multiplied by itself with the any exponent the exponents are added .

 a^m \div a^n = a^{m-n}

:- When a number is divided by itself with the any exponent the exponents are subtracted.

 a^{-n} = \dfrac{1}{a^n}

 a^{1/n} = \sqrt[n]{a}

Solution :-

 16^4 \: \times  \sqrt{16^{-1/4}}

 16^4 \times 16^{-1/8}

 = 16^{4 + (-1/8)}

 = 16^{4 - \frac{1}{8}}

 = 16^{\frac{32-1}{8}}

 = 16^{\frac{31}{8}}

 = 16^{3}\sqrt[8]{16^7}


thugriderx: i think its right but my teacher says otherwise....
Anonymous: You can ask me anything about the question !
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