Question

16. (4x + 5y)^2-1 factorise​

Answer 1

Answer:

${(4x + 5y)}^{2} - 1 \\ = {(4x + 5y)}^{2} - 1^{2} \\ = (4x + 5y + 1)(4x + 5y - 1) \: \\ are \: the \: required \: factors \: of \: the \: \\ given \: \: expression. \\ formula \: used : \\ {a}^{2} - b^{2} = (a + b)(a - b)$

Answer 2

(4x-5y)^2-1

(4x-5y)^2-1^2

(4x-5y-1)(4x-5y+1)