Math, asked by anupkmehrotra, 1 year ago

16-[5-2+{7 of 2-(6÷3×2-1+3)}]

Answers

Answered by DSamrat
23
Hey.

Here is the answer.

16-[5-2+{7 of 2-(6÷3×2-1+3)}]

= 16-[5-2+{7 of 2-(2×2-1+3)}]

= 16-[5-2+{7 of 2-(4-1+3)}]

= 16-[5-2+{7 of 2-(7-1)}]

= 16-[5-2+{7 of 2-(6)}]

=16-[5-2+{7 of 2-6}]

= 16-[5-2+{14-6}]

=16-[5-2+8]

=16-[13-2]

= 16-[11]

= 5

Thanks.
Answered by Anonymous
12
⭐⭐Hello friend...Ur answer is here⤵⤵

⚫16-[5-2+{7 of 2-(6÷3×2-1+3)}]

= 16-[5-2+{7 of 2-(2×2-1+3)}]

= 16-[5-2+{7 of 2-(4-1+3)}]

= 16-[5-2+{7 of 2-(6)}]

= 16-[5-2+{14 -(6)}]

= 16-[5-2+{8}]

= 16-[5-2+8]

= 16-[11]

= 5

= 41

I HOPE IT IS HELPFUL TO YOU ☺
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