Question

16. 5, 9, 25, 89, ?, 1369 [IBPS Clerk (Pre) 2016] (a) 343 (b) 355 (c) 349 (d) 341 (e) 345
solve it with explanation​

Answer 1

Answer:

89+64*4

89+256

345

simply add by 4^n

4 in 1

4^2 in2

4^3 in 3

Answer 2

Answer:

15 + (7^3 + 7) = (15 + 350) = 365.

365 + (6^3 + 6) = 365 + 222 = 587.

587 + (5^3 + 5) = 587 + 130 = 717.

717 + (4^3 + 4) = 717 + 68 = 785.

785 + (3^3 + 3) = 785 + 30 = 815.

815 + (2^3 + 2) = 815 + 10 = 825.

So, the next number is 825 and the series is 15, 365, 587, 717, 785, 815, 825.

Step-by-step explanation:

above Q Ans