16.8 litre gas containing h2 and o2 is formed at ntp on electrolysis of water. what should be the weight of electrolysed water
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We know, electrolysis rxn. of H2O
2H2O------>2H2+O2
=> H2 and O2 are liberated in the ratio 2:1
Assume H2-2x litres and O2-x litres
=>3x=16.8
Therefore x=16.8/3=5.6
=> volume of electrolysed H2O(g)=2*5.6=11.2
No. of moles of H2O=11.2/22.4=0.5
Weight of H2O electrolysed=0.5*18 g=9 g
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