Question

16 (a+b)^2-9 (a-b)^2 factorise​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

16[a+b]^2=16[a^2+b^2+2ab]

16[a+b]^2=16[a^2+b^2+2ab]9(a-b)^2=9(a^2+b^2-2ab

16[a+b]^2=16[a^2+b^2+2ab]9(a-b)^2=9(a^2+b^2-2ab16 (a+b)^2-9(a-b)^2

16[a+b]^2=16[a^2+b^2+2ab]9(a-b)^2=9(a^2+b^2-2ab16 (a+b)^2-9(a-b)^216a^2+16b^2+32ab-9a^2-9b^2+18ab

16[a+b]^2=16[a^2+b^2+2ab]9(a-b)^2=9(a^2+b^2-2ab16 (a+b)^2-9(a-b)^216a^2+16b^2+32ab-9a^2-9b^2+18ab7a^2+7b^2+50ab

Hope this will help you