16. A body falls from the top of a building and reaches
the ground 2.5 s later. How high is the building ?
9,8 m s-2
(Take a
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Answer:
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Answered by
1
Answer:
30.625 m I hope it will help you.
s = ut + 1/2at^2
here u = 0 due to free fall
s = 1/2at^2
s = 1/2×9.8×2.5×2.5
s = 30.625 m
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