Question

16. A body is moving with an acceleration o
5m/s^2 started with a velocity of 10m/s.
what will be the distance travelled in 10s?​

Answer 1

Answer:

350 m

Explanation:

Given:

Acceleration (a) = 5 m/s²

Initial velocity (u) = 10 m/s

Time (t) = 10 seconds

To find:

Distance travelled (s)

Method to find:

s = ut + 1/2at²

⇒ s = (10*10) + (1/2 * 5 * 10²)

⇒ s = 100 + 250

⇒ s = 350 m

Hence, the distance travelled by the body in 10 seconds is 350 m.

Answer 2

Given

• Acceleration = 5 m/s²
• Velocity = 10 m/s
• Time = 10 sec

To Find

• Distance Covered

Solution

● v = u + at

● v²-u² = 2as

✭ Final Velocity :

→ v = u + at [First Equation of Motion]

→ v = 10 + 5 × 10

→ v = 10 + 50

→ v = 60 m/s

━━━━━━━━━━━━━━━━━━━━━━━

✭ Distance Covered :

→ v²-u² = 2as [Third Equation of Motion]

→ 60²-10² = 2 × 5 × s

→ 3600 - 100 = 10s

→ 3500 = 10s

→ 3500/10 = s

→ Distance = 350 m