Question

16. A bullet moving with a velocity of 200 cm/s
penetrates a wooden block and comes to rest after
traversing 4 cm inside it. What velocity is needed
for travelling distance of 9 cm in same block :-​

Answer 1

Answer:

/s

v

2

−u

2

=2as

0−(200)

2

=2a×4

⇒a=5000cm/s

2

Now initial velocity to travel 6 cm,

0−u

2

=−2×5000×6

⇒u=244.9cm/s

Answer 2

v

2

−u

2

=2as

0−(200)

2

=2a×4

⇒a=5000cm/s

2

Now initial velocity to travel 6 cm,

0−u

2

=−2×5000×6

⇒u=244.9cm/s