Question

16. A can do a certain job in 25 days which B
alone can do in 20 days. A started the work
and was joined by B after 1,0 days. The work
lasted for​

Answer 1

Answer:

Lcm of 25,20 is 100

Total work is 100

A_100/25=4

B_100/20=5

A*10+(A+B)*X=100

4*10+9*X=100

9*X=60

X=20/3

A work 10 days 20/3+10=50/3