16. A cylindrical tube, open at both ends, is made of metal
. The internal
diameter of the tube is 10.4 cm and its length is 25 cm. The thickness of
the metal is 8 mm everywhere. Calculate the volume of the metal.
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Answer ---
thr internal diameter of the cylindrical tube which open at both ends = 10.4 cm
Radius (r) = 10.4/2 = 5.2 cm
the thickness of the metal =8 mm or 0.8 cm
So, the Outer Radius (R) = thickness of metal + internal radius
thus, (R) = 0.8+5.2 cm
(R) = 6 cm
the height of tube = 25 cm
Now, the volume of metal = π h( R^ - r^)
= 22/7 ×25 (6^ - 5.2 ^)
= 550/7 ( 36 - 27.04)
= 550/7 ( 8.96)
= (550×8.96) ÷ 7
= 4928/7
= 704
Thus , The Volume of metal = 704 cm cube
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