Math, asked by raviprasad16, 8 months ago

16.
A dishonest milkman adds 20% water to the existing quantity of milk and sells it at the same
price for which he buys it. After selling a few litres of the mixture he is caught and has to
pay fine of Rs.200. After paying the fine he realises that he has suffered a loss of Rs.100.
How many litres of the mixture did he sell if he bought pure milk for Rs.10 per litre?
1) 100 litres
2) 85 litres
3) 50 litres
4) 60 litres​

Answers

Answered by amitnrw
6

Given : A dishonest milkman adds 20% water to the existing quantity of milk and sells it at the same  price for which he buys it.

After selling a few litres of the mixture he is caught and has to  pay fine of Rs.200. After paying the fine he realises that he has suffered a loss of Rs.100.

Solution:

Let say existing quantity of milk = M  litre

Added 20 % water = (20/100)M  = 0.2M litre

Total Mixture = M + 0.2M = 1.2M litre

Cost Price = 10M  Rs

Selling Price = 1.2M * 10 = 12M  Rs

Profit = 2M Rs

Fine = 200 Rs

Loss = 100 Rs

2M - 200 = - 100

=> 2M = 100

=> M = 50

Total Mixture = 1.2M  = 60 Litre  

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60  litres of the mixture sold

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