Question

16. A field in the form of a parallelogram, has one of its diagonals 42 m long and
the perpendicular distance of this diagonal from either of the outlying vertices is
10.8m. Find the area of the field.

Answer 1

$\mathtt{\huge{\bf{\underline{\red{Answer :-}}}}}$

• A field in the form of a parallelogram, has one of its diagonals 42 m long .

• The perpendicular distance of this diagonal from either of the outlying vertices is 10.8m

To find :-

• The area of the field.

Solution :-

According to the question,

It has one of its diagonals 42 m long.

Diagonal = d = 42m

Perpendicular distance from either of the outlying vertices = 10.8 m

• The first hieght is 10.8 m.

• The second hieght is 10.8 m.

Area of the field = $\dfrac{L1 + L2 }{2}$ × d

➝ $\dfrac{10.8 + 10.8 }{2}$ × 42

➝ $\dfrac{21.6 }{2}$ × 42

➝ 21.6 × 42

➝ 453.6 m²

➡ The area of the field is 453.6 m² .

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