Question

16.
a) Find the sum of all three digit numbers which are divisible by 11
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Answer 1

Answer : 44550

Step-by-step explanation:

The three digit numbers start from 100 to 999

Those three digit nunbers that are divisible by 7 are as follows:

Those three digit nunbers that are divisible by 7 are as follows:110, 121,132 ......... 990

here,

first term=110

common difference=121-110=11

and last term = 990

an = 990

a+(n-1) d= 990

110+(n-1) 11=990

110+11n-11 =990

99+11n = 990

11n= 891

n=81

Sum = n/2 [2a+(n-1) d]

= n/2(a + an)

81/2 (110 + 990)

81/2 (1100)

550×81

44550

Please mark as brainliest....

Answer 2

Step-by-step explanation:

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