16. A floor which measures 15m x 8m is to be
laid with tiles measuring 50 cm x 25cm. Find
the number of tiles required
Further, if a carpet is laid on the floor so that
a space of 1 m exists between its edges and
the edges of the floor, what fraction of the floor
is left uncovered,
Answers
Answer:
We know, 50cm=0.5m and
25cm=0.25m
Tiles along the length of the room=
0.5
15
=30 tiles
Tiles along the length of the room=
0.25
8
=32 tiles
Total number of tiles required =30×32
=960 tiles
To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.
Therefore,
(15−2)m(8−2)m
=(13×6)m
=78m
2
Therefore, the room area is 15×8
=120m
2
The carpet area is 78m
2
The fraction of the area uncovered is
=
120
120−78
=
120
42
=
20
7
Answer:
know, 50cm=0.5m and
25cm=0.25m
Tiles along the length of the room=
0.5
15
=30 tiles
Tiles along the length of the room=
0.25
8
=32 tiles
Total number of tiles required =30×32
=960 tiles
To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.
Therefore,
(15−2)m(8−2)m
=(13×6)m
=78m
2
Therefore, the room area is 15×8
=120m 2
The carpet area is 78m 2
The fraction of the area uncovered is
= 120120−78 =12042 =207