(16) A fluoride disposal plant was constructed to carry out the following reactions
F2 + 2NaOH → ½ O2 + 2NaF + H2O
2NaF + CaO + H2O → CaF2 + 2NaOH
As the plant operated, enough lime was added from time to time to just bring out the
complete precipitation of fluorine as CaF2. Over a period of time 2000 kg of fluorine was fed
into the plant and 6000 kg of lime was added. What was the percentage utilization of lime?
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Answer:
(0028)
No of moles of lime required =
56
10000×10
3
(m) out of CaO=56
=1.286×10
5
No. of moles of F
2
fed =
19
1900×10
3
=105 moles
2F
2
+4 NaOH→4NaF+2H
2
O+O
2
−−−(1)
According to given reaction, moles formed of NaF only its half used in second reaction of below 2NaF+CaO+H
2
O→CaF
2
+NaOH
2
2×10
5
=105
2
1
×10
5
=0.5×10
5
% utilisation of lime =
no. of mole of lime required
No of mole of lime utilised
=
1.786×10
5
0.5×10
5
×100
=28%
answer =(0.028)
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