16. A is 4 years older than B, and half of A's age exceeds one-sixth of B's age by 8 years. Find their ages.
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Answer:
A = 10, B = 6
Step-by-step explanation:
According to the question, A = B + 4
Also according to the question, A/2 = B/6 + 8
The second equation can be written as 3A = B + 24 (when multiplied with 3)
So, we get the equations as A - B = 4 and 3A - B = 24.
By elimination method, we get 3A - 3B = 12 and 3A - B = 24.
Cancelling 3A term, -2B = -12, B = 6 yrs.
A = B + 4, so A = 10 yrs.
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