Question

16. A man deposited 8,000 @ 5% p.a. in the name of his two sons aged 15 and 12 years in such a
way that at their age of 18, both of them get equal amounts. What are the sums in each name?
ns. [4,286, 3,714]​

Answer 1

p=8000/2=4000 R=5% N = 3 year and 6 year

I = P×R×N/100

=4000×5×3/100

=40×15

=600

=4000×5×6/100

=40×30

=1200

1 SON TAKE TOTAL AMOUNT IS 4000+600= 4600

2 SON TAKE TOTAL AMOUNT IS 4000+1200=5200