Question

16. A motorcyclist at t= 0, situated at a distance s = 12 m behind a car, moves with a velocity v = 8 m/s. If the car starts
accelerating from rest with a = 2 m/s2 at t = 0, when do they meet
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Answer 1

They meet when Displacement of both is same.

S1 be Car and S2 be Motorcylists displ

S1=S2

1/2at^2=8t+12 (Since motor is 12m behind it has to cover that too to be

equal)

1/2(4)t^2=8t+12

2t^2-8t-12=0

T=.....(something)

Subsitute ia either s1 or s2 to get S.