Question

16. A park has the shape of a regular decagon with each side 51 m. Find the perimeter of the park. If the cost of fencing is 41.30 per metre, calculate the cost of fencing the park.​

Answer 1

Answer:

As per question ,

each side = 51 m

we know, perimeter is actually the sum of all sides

Therefore , 51 x 10 m

= 510 m

Now , Cost of fencing = perimeter x cost per metre

= 510 x 41.30

= 21063 rupees

Answer 2

Given :

A park has the shape of a regular decagon with each side 51 m.

The cost of fencing is 41.30 per metre.

To find :

Find the perimeter of the park and the cost of fencing the park.​

Solution :

Side of decagon = 51 m

∵ Perimeter of decagon = 10a         [a = Length of each side]

Now putting values,

⇒ Perimeter of decagon = 10 × 51

⇒ Perimeter of decagon = 510 m

Now,

Perimeter = 510 m

Rate of cost of fencing = Rs. 41.30/m

∵ Cost of fencing = Perimeter × Rate of fencing

Substituting values,

⇒ Cost of fencing = 510 × 41.3

⇒ Cost of fencing = Rs. 21063

∴ Perimeter of decagon = 510 m and cost of fencing the park = Rs. 21063.