Question

 16
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance D1 in the first 10 seconds and distance D2 in the next 10 seconds then, 
(a) D2 = D1
(b) D2 = 2D1
(c) D2 = 3D1
(d) D2 = 4D1​

Answer 1

Answer:

C

Explanation:

The distance traveled in first 10 seconds is 0.5XaX100 = 50a

The distance traveled in 20 seconds = 0.5XaX400 = 200a.

The distance traveled in last 10 seconds is 150a.

Hence D2 = 3D1