Question

16. A particle starts from a point with a velocity of +6.0
m/s and moves with an acceleration of -2. 0m/s2.
Show that after 6 s the particle will be at the starting
point.
C1/1​

Answer 1

Answer:

Explanation:

S=UT - 1/2 at

We got-U= 6m/s

A=-2m/s Square

Time - 6s

Thus,S=6×6-1/2×2×5 square

=36 - 1/2×50

=36 - 25

=11m(ans)

Hope it helps!

Answer 2

• Explanation:- 1st of all you have to understand the meaning of the 3 Equations.
• here we will use S= ut + 1/2 at×t
• here s means displacement.
• according to the question to prove that after 6 sec it will be at starting point, we have to prove that s will be 0 after 6 sec. this is basic requirement.
• we will put the value of different quantities given.
• 6×6-1/2×2×6×6=0
• s=0