Question

16
A road roller has a diameter of 84 cm and length 2 m. How much area would it cover in 10 complete revolutions?​

Answer 1

Answer →

In 10 revolution given roller can cover 52.8²m area .

Solution →

Given that

• Length of cylinder = 2m or 200 cm
• Radius of cylinder = 84/2 = 42 cm

As we know that surface area of cylinder is

→ 2πrh

Then surface area = 2×π×42×200

→ 369600÷7

→ 52800 cm²

→ 52800÷ 10000

→ 5.28 m²

In 10 revolution →

5.28 ×10 = 52.8 m²

hope it helps

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Answer 2

SOLUTION:-

Given:

A road roller has a diameter of 84cm. & length is 2m.

To find:

The area would cover in 10 complete revolutions.

Explanation:

•Diameter= 84cm

•Radius = 84/2 = 42cm

•Length is 2m

In cm is 2 ×100cm = 200cm

Formula of the curved surface area of the cylinder;

=) 2πrh

$= > 2 \times \frac{22}{7} \times 42 \times200 \\ \\ = > \frac{44}{7} \times 42 \times 200 \\ \\ = > (44 \times 6 \times 200) {cm}^{2} \\ \\ = > 52800 {cm}^{2}$

Therefore,

Area of 1 revolutions= 52800cm².

Area of 10 complete revolutions;

=) (10 × 52800)cm²

=) 528000cm²

If we can convert in m²

So,

$= > 528000 \times \frac{1}{100} \times \frac{1}{100} {m}^{2} \\ \\ = > \frac{528000}{10000} {m}^{2} \\ \\ = > 52.8 {m}^{2}$

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