Question

16. A sphere of mass 50gm is suspended by a string in an electric field of intensity 5NC- acting vert
upward. If the tension in the string is 520 millinewton, the charge on the sphere is (g = 10ms
1) 4 x 10-30
2) 4 x 10-30
3) 8 x 10-0
+ -8x10-3 C
17. A and B are two points separated by a distance 5cm. Two charges 10uC and 20uC are placed
and B. The resultant electric intensity at a point P outside the charges at a distance 5cm from 100
1) 54 x 106 N/Caway from 10uC
2) 56 x 106 N/C towards 10uC
3) 9 x 106 NC
away
from 10 uc
4) zero
APFX SERIES for Sri Chaitanya CBSE XIL Stud
2​

Answer 1

Explanation:

16 question answer is -4*10^-3

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