Question

16.
A toy is in the form of a right circular cylinder with a
hemisphere on one end and a cone on the other.
The height and radius of base of the cylindrical part
are 13 cm and 5 cm respectively. The radius of
hemisphere and base of the conical part are same
as that of the cylinder. Calculate the surface area
of the toy, if the height of the cone is 12 cm.(Take *
= 22/7).​

Answer 1

Step-by-step explanation:

Volume of each cube = 64 cm3

∴ Total volume of the two cubes = 2 × 64 cm3

= 128 cm3

Let the edge of each cube = x

∴ x3 = 64 = 43

∴ x = 4 cm

Now, Length of the resulting cuboid l = 2x cm

Breadth of the resulting cuboid b = x cm

Height of the resulting cuboid h = x cm

∴ Surface area of the cuboid = 2 (lb + bh + hl) = 2[(2x . x) + (x . x) + (x . 2x)]

= 2[(2 × 4 × 4) + (4 × 4) + (4 × 2 × 4)] cm2

= 2 [32 + 16 + 32] cm2 = 2[80] cm2 = 160