Question

16. A train accelerates uniformly from 30 Km/h to 60 Km/h in 30 sec. Find the distance covered

by it during these 30 sec. (Ans: 375m)
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Answer 1

Hey there here is your answer

Answer 2

Answer:

change in velocity = 30 km/h

time = 30 s

acceleration = 30,000 m / 3600s /30s

acceleration = 5/18 $m/s^{2}$

acceleration = 0.277 $m/s^{2}$

distance traveled = average speed X time

distance traveled =45 km/h X 30/3600 h

distance traveled = 45 km/h X 1/120h

distance traveled = 0,375 km

distance traveled = 375 m

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