Math, asked by Anonymous, 10 months ago

16. A train travels 136/3 km every hour for the first 7/2 hours after leaving a station. After that it travels 101/2every hour for the next 5/2hours.What distance does the train travel during the six hours?

Please explain me step by step (if you know)...​

Answers

Answered by Anonymous
38

♥ ᕼOᒪᗩ ᗰᗩTE ♥

Here is your answer:-

Given:-

Speed of train=136/3km per hour

Time=7/2 hours

To find :-

Distance =Speed * Time

= 136/3*7/2=476/3=158 2 /3

We know that:-

Speed =101/2km per hour

Time= 5/2 hours

To find:-

Speed=101/2*5/2=504/4=126 1/4

Therefore total distance = 158 2/3+126 1/4=3419/12=296 7/12

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Answered by Anonymous
29

Step-by-step explanation:

Speed of a train = 136/3 km per hour

Time = 7/2 hours

Distance =speed x time

= 136/3 x 7/2

=476/3

=158 2/3

Speed=101/2 km per hour

Time=5/2 hours

Speed = 101/2 x 5/2

=505/4

=126 1/4

Therefore, total distance = 158 2/3 + 126 1/4

=476/3 + 505/4

= (1904+1515)/12

= 3419/12

=296 7/12

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