Question

16. A tree is broken at a height of 6 m from the ground and its top touches the ground at a distance of 8 m from the base of the tree. find the original height of the tree.



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Answer 1

Answer:

16 m

Step-by-step explanation:

We are given that a tree is broken at a height of 6 m from the ground

So, Right triangle is formed

So. Perpendicular = 6 m

Its top touches the ground at a distance of 8 m from the base of the tree.

So, Base = 8 m

Hypotenuse^2 = Perpendicular^2+Base^2Hypotenuse2=Perpendicular2+Base2

Hypotenuse^2 = 6^2+8^2Hypotenuse2=62+82

Hypotenuse = \sqrt{6^2+8^2}Hypotenuse=62+82

Hypotenuse =10Hypotenuse=10

Original height = 10+6 = 16 m

Hence the original height of tree is 16 m

Step-by-step explanation:

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Answer 2

Answer:

ORIGINAL LENGTH OF TREE IS 16m

Step-by-step explanation:

PARAMETERS GIVEN,

PERPENDICULAR HEIGHT=6cm

BASE LENGTH=8m

SO,

LET THE LENGTH OF THE BROKEN PART BE x

SO,

WE KNOW,

(P)²+(B)²=(H)²

(6m)²+(8m)²=(x)²

36m²+64m²=x²

100m²=x²

x=$\sqrt{100m^{2} }$

x=10m

SO,

ORIGNAL HEIGHT=PERPENDICULAR HEIGHT+LENGTH OF BROKEN PART

                              = 6m+10m

                              = 16m

SO,

ORIGINAL LENGTH OF TREE IS 16m

I HOPE YOU UNDERSTOOD THE QUESTION!!!