Question

16. A uniform metre scale of weight 20 gf is pivoted
at its zero mark. Calculate (a) the moment of
force that depresses the scale and (b) what
would be the magnitude of least force applied
on it to make it horizontal?​

Answer 1

Answer:

Hence it will have 500gfcm to depress the rule.

As we have to apply least force, hence the distance should be maximum, i.e, at the end of meter rule. Equating 500gfcm=100×x

x=500/100gf. Hence there would be of 5gf force at least to make it balanced along horizontal.