Question

16. A water reservoir is 12 m long, 9m wide, and 6m
high. Assuming that the reservoir is full, if the water is
being pumped out at the rate of 180 litres per minute,
in how many hours will the reservoir be empty? please give answer with solution​

Answer 1

Step-by-step explanation:

so 60 hrs to empty the tank

Answer 2

The number of hours required in which the reservoir will be empty is 60 hours.

Step-by-step explanation:

Given:

A water reservoir is 12 m long, 9m wide, and 6m high.

Assume that the reservoir is full of water.

The water was pumped out at the rate is 180 liters per minute,

To Find:

The number of hours required in which the reservoir will be empty.

Formula Used:

Volume of reservoir  $V= p\times q\times r$      --------------- formula no.01.

Where  p= length of reservoir

            q =width of reservoir

             r= height of the reservoir

The water pumped out at the rate $M=\frac{V}{t}$   --------------formula no.02

Where   V= Volume of a reservoir

             t = The number of hours required in which the reservoir will be empty.

Solution:

As given-  a water reservoir is 12 m long, 9m wide, and 6m high. Assume that the reservoir is full of water.

      p =12 meter, q= 9meter and r = 6 meter

Putting the value of p,q, and r in formula no.01.

Volume of reservoir $V= 12 \times 9 \times6$

                                      $= 648 \ meter^{3}$

As given - the water was pumped out at the rate is 180 liters per minute.

$M=180\ liter/minute = 180\times 0.001 \times 60\ meter^{3}/hours$

                                     $= 10.8 meter^{3} /hours$

Putting value of M and V in formula no.02.

$10.8=\frac{648}{t}$

$t=\frac{648}{10.8}$

   $=60 \ hours$

Thus, the number of hours required in which the reservoir will be empty is 60 hours.