Question

16+a²+b²=0 find the value
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Answer 1

Answer:

$16 + {a}^{2} + {b}^{2} = 0 \\ {a }^{2} + {b}^{2} = - 16$

Answer 2

Answer:

a^2 +b^2=16 is the ans i think so

Step-by-step explanation:

16+ a^2+b^2=0

16+(a-b) (a+b)=0

16 + a (a + b) -b (a + b) =0

16 + a^2 +ab - ab +b^2 =0

16 a^2 + b^2 =0

a^2 + b^2=16

hope this help you