Math, asked by mahiujal001kd, 1 month ago

16(a³b²c²+a²b³c²a²b²c³)÷8a²b²c² Divide the following​

Answers

Answered by saka82411
1

Answer:

2( a+b+c)

Step-by-step explanation:

Take a²b²c² as common.

:- 16× a²b²c²( a+ b+c) / 8a²b²c²

= 2 (a+b+c).

Hope it helps.

Answered by Abhijaybishnoi
0

Step-by-step explanation:

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