Question

16 added to the sum of the first few terms of the Arithmetic sequence 9,11,13...gave 256.how many terms were added?

Answer 1

Let n term we add to get 256

Sn + 16 =256
Sn = n/2[2a+(n-1)d]
n/2[2a+(n-1)d]=256
a=9, d= 2
n/2[18+(n-1)2]=256
Now u calculate n

Answer 2

Answer:

16 +9,11,13....31 =256

12th term of the sequence = 256

16+9,11,13,......31 = 256

Step-by-step explanation: