Question

16. Ajay is three years older than Vijay. Six years ago, Ajay's age was four times Vijay's
age. Find the ages of Ajay and Vijay.​

Answer 1

Lets guess Ajay’s present age is = X yrs, Vijay’s age = Y yrs

8 years ago, Ajay’s Age = X-8 yrs, Vijay’s age = Y-8 yrs

As per question it is 4/3 of Y(i.e. Vijay’s Age) , So it is X = 4/3 * Y-8…………(1)

Now after 8 yrs i.e. Present age, X = 6/5 * Y………….(2)

Compare (1) with (2),

6/5Y = 4/3Y - 32/3

By Simplifying above equation step by step,

6/5Y - 4/3Y = -32/3

18Y - 20Y = -32*15/3

-2Y = -32*5

Y = 160/2

Y= 80 yrs i.e. Vijay’s present Age

Since X = 6/5 * Y = 6/5 * 80

X = 6*20*4/5

X = 64 yrs i.e. It is Present Age of Ajay

Answer 2

Step-by-step explanation:

Let, Ajay's age=x

So Vijay's age =x-3

Now, ATQ,

(x-6)=4(x-3-6)

$\implies$ (x-6)= (4x-36)

$\implies$ -4x+x= -36+6

$\implies$-3x= -30

$\implies$3x=30

$\implies$x=(30/3)=10

Hence, Ajay's age is 10 years and Vijay's age is 7 years.

Please mark me brainliest if my answer had helped.